1/5x^2=80

Solution for 1/5x^2=80 equation:

1/5x^2=80

We move all terms to the left:

1/5x^2-(80)=0


Domain of the equation: 5x^2!=0

x^2!=0/5

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-80*5x^2+1=0

Wy multiply elements

-400x^2+1=0

a = -400; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-400)·1
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*-400}=\frac{-40}{-800}
=1/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*-400}=\frac{40}{-800}
=-1/20
$